https://leetcode-cn.com/problems/subtract-the-product-and-sum-of-digits-of-an-integer/
/*
* @Author: Goog Tech
* @Date: 2020-08-15 21:10:15
* @LastEditTime: 2020-08-15 21:15:56
* @Description: https://leetcode-cn.com/problems/subtract-the-product-and-sum-of-digits-of-an-integer/
* @FilePath: \leetcode-googtech\#1281. Subtract the Product and Sum of Digits of an Integer\Solution.java
* @WebSite: https://algorithm.show/
*/
/*
* @lc app=leetcode.cn id=1281 lang=java
*
* [1281] 整数的各位积和之差
*/
// @lc code=start
class Solution {
public int subtractProductAndSum(int n) {
int p = 1, s = 0;
// n % 10 即获取数值最后一位数字, n / 10 即删去数值的最后一位数字
while(n != 0) {
p *= n % 10;
s += n % 10;
n /= 10;
}
return p - s;
}
}
// @lc code=end
'''
Author: Goog Tech
Date: 2020-08-15 20:59:46
LastEditTime: 2020-08-15 21:15:09
Description: https://leetcode-cn.com/problems/subtract-the-product-and-sum-of-digits-of-an-integer/
FilePath: \leetcode-googtech\#1281. Subtract the Product and Sum of Digits of an Integer\Solution.py
WebSite: https://algorithm.show/
'''
#
# @lc app=leetcode.cn id=1281 lang=python
#
# [1281] 整数的各位积和之差
#
# @lc code=start
class Solution(object):
def subtractProductAndSum(self, n):
"""
:type n: int
:rtype: int
"""
# 先将 n 转换为字符串类型,然后再其转换为列表类型并赋值给alist
alist = list(str(n))
# 初始化乘积与和的值
p, s = 1, 0
# 遍历列表元素,将元素逐个转换为整型并求出乘积和与相加和
for element in alist:
p *= int(element)
s += int(element)
# 返回结果
return p - s
# @lc code=end