https://leetcode-cn.com/problems/merge-two-binary-trees/
/*
* @Author: Goog Tech
* @Date: 2020-07-29 08:34:34
* @Description: https://leetcode-cn.com/problems/merge-two-binary-trees/
* @FilePath: \leetcode-googtech\#102. Binary Tree Level Order Traversal\617.合并二叉树.java
*/
/*
* @lc app=leetcode.cn id=617 lang=java
*
* [617] 合并二叉树
*/
// @lc code=start
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
// 迭代法
public TreeNode mergeTrees(TreeNode t1, TreeNode t2) {
// 若其中一棵树为空,则返回另一颗树作为结果
if(t1 == null || t2 == null) return t1 == null ? t2 : t1;
// 若两颗树当前节点都不为空,则将它们的值相加,并且对它们的左右孩子节点进行递归合并
t1.val += t2.val;
t1.left = mergeTrees(t1.left, t2.left);
t1.right = mergeTrees(t1.right, t2.right);
return t1;
}
}
// @lc code=end
'''
@Author: Goog Tech
@Date: 2020-07-29 09:01:01
@LastEditTime: 2020-07-29 09:12:01
@Description: https://leetcode-cn.com/problems/merge-two-binary-trees/
@FilePath: \leetcode-googtech\#102. Binary Tree Level Order Traversal\617.合并二叉树.py
'''
#
# @lc app=leetcode.cn id=617 lang=python
#
# [617] 合并二叉树
#
# @lc code=start
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
# 迭代法
def mergeTrees(self, t1, t2):
"""
:type t1: TreeNode
:type t2: TreeNode
:rtype: TreeNode
"""
# 若其中一棵树为空,则返回另一颗树作为结果
if not t1: return t2
if not t2: return t1
# 若两棵树当前节点都不为空,则将它们的值相加,并且对它们的左右孩子节点进行递归合并
t1.val += t2.val
t1.left = self.mergeTrees(t1.left, t2.left)
t1.right = self.mergeTrees(t1.right, t2.right)
return t1
# @lc code=end