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English Version

题目描述

给定两个整数数组ab,计算具有最小差绝对值的一对数值(每个数组中取一个值),并返回该对数值的差

示例:

输入:{1, 3, 15, 11, 2}, {23, 127, 235, 19, 8}
输出: 3,即数值对(11, 8)

提示:

  • 1 <= a.length, b.length <= 100000
  • -2147483648 <= a[i], b[i] <= 2147483647
  • 正确结果在区间[-2147483648, 2147483647]内

解法

Python3

class Solution:
    def smallestDifference(self, a: List[int], b: List[int]) -> int:
        a.sort()
        b.sort()
        i, j, res = 0, 0, 2147483647
        m, n = len(a), len(b)
        while i < m and j < n:
            if a[i] == b[j]: return 0
            res = min(res, abs(a[i] - b[j]))
            if a[i] > b[j]: j += 1
            else: i += 1
        return res

Java

class Solution {
    public int smallestDifference(int[] a, int[] b) {
        Arrays.sort(a);
        Arrays.sort(b);
        int m = a.length, n = b.length;
        int i = 0, j = 0;
        long res = Long.MAX_VALUE;
        while (i < m && j < n) {
            if (a[i] == b[j]) return 0;
            res = Math.min(res, Math.abs((long) a[i] - (long) b[j]));
            if (a[i] > b[j]) ++j;
            else ++i;
        }
        return (int) res;
    }
}

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