Skip to content

Latest commit

 

History

History
119 lines (63 loc) · 2.23 KB

File metadata and controls

119 lines (63 loc) · 2.23 KB

中文文档

Description

Given a m * n matrix mat of ones (representing soldiers) and zeros (representing civilians), return the indexes of the k weakest rows in the matrix ordered from the weakest to the strongest.

A row i is weaker than row j, if the number of soldiers in row i is less than the number of soldiers in row j, or they have the same number of soldiers but i is less than j. Soldiers are always stand in the frontier of a row, that is, always ones may appear first and then zeros.

 

Example 1:

Input: mat = 

[[1,1,0,0,0],

 [1,1,1,1,0],

 [1,0,0,0,0],

 [1,1,0,0,0],

 [1,1,1,1,1]], 

k = 3

Output: [2,0,3]

Explanation: 

The number of soldiers for each row is: 

row 0 -> 2 

row 1 -> 4 

row 2 -> 1 

row 3 -> 2 

row 4 -> 5 

Rows ordered from the weakest to the strongest are [2,0,3,1,4]

Example 2:

Input: mat = 

[[1,0,0,0],

 [1,1,1,1],

 [1,0,0,0],

 [1,0,0,0]], 

k = 2

Output: [0,2]

Explanation: 

The number of soldiers for each row is: 

row 0 -> 1 

row 1 -> 4 

row 2 -> 1 

row 3 -> 1 

Rows ordered from the weakest to the strongest are [0,2,3,1]

 

Constraints:

  • m == mat.length
  • n == mat[i].length
  • 2 <= n, m <= 100
  • 1 <= k <= m
  • matrix[i][j] is either 0 or 1.

Solutions

Python3

Java

...