Design a search autocomplete system for a search engine. Users may input a sentence (at least one word and end with a special character '#'
).
You are given a string array sentences
and an integer array times
both of length n
where sentences[i]
is a previously typed sentence and times[i]
is the corresponding number of times the sentence was typed. For each input character except '#'
, return the top 3
historical hot sentences that have the same prefix as the part of the sentence already typed.
Here are the specific rules:
- The hot degree for a sentence is defined as the number of times a user typed the exactly same sentence before.
- The returned top
3
hot sentences should be sorted by hot degree (The first is the hottest one). If several sentences have the same hot degree, use ASCII-code order (smaller one appears first). - If less than
3
hot sentences exist, return as many as you can. - When the input is a special character, it means the sentence ends, and in this case, you need to return an empty list.
Implement the AutocompleteSystem
class:
AutocompleteSystem(String[] sentences, int[] times)
Initializes the object with thesentences
andtimes
arrays.List<String> input(char c)
This indicates that the user typed the characterc
.- Returns an empty array
[]
ifc == '#'
and stores the inputted sentence in the system. - Returns the top
3
historical hot sentences that have the same prefix as the part of the sentence already typed. If there are fewer than3
matches, return them all.
- Returns an empty array
Example 1:
Input ["AutocompleteSystem", "input", "input", "input", "input"] [[["i love you", "island", "iroman", "i love leetcode"], [5, 3, 2, 2]], ["i"], [" "], ["a"], ["#"]] Output [null, ["i love you", "island", "i love leetcode"], ["i love you", "i love leetcode"], [], []] Explanation AutocompleteSystem obj = new AutocompleteSystem(["i love you", "island", "iroman", "i love leetcode"], [5, 3, 2, 2]); obj.input("i"); // return ["i love you", "island", "i love leetcode"]. There are four sentences that have prefix "i". Among them, "ironman" and "i love leetcode" have same hot degree. Since ' ' has ASCII code 32 and 'r' has ASCII code 114, "i love leetcode" should be in front of "ironman". Also we only need to output top 3 hot sentences, so "ironman" will be ignored. obj.input(" "); // return ["i love you", "i love leetcode"]. There are only two sentences that have prefix "i ". obj.input("a"); // return []. There are no sentences that have prefix "i a". obj.input("#"); // return []. The user finished the input, the sentence "i a" should be saved as a historical sentence in system. And the following input will be counted as a new search.
Constraints:
n == sentences.length
n == times.length
1 <= n <= 100
1 <= sentences[i].length <= 100
1 <= times[i] <= 50
c
is a lowercase English letter, a hash'#'
, or space' '
.- Each tested sentence will be a sequence of characters
c
that end with the character'#'
. - Each tested sentence will have a length in the range
[1, 200]
. - The words in each input sentence are separated by single spaces.
- At most
5000
calls will be made toinput
.
class Trie:
def __init__(self):
self.children = [None] * 27
self.v = 0
self.w = ''
def insert(self, w, t):
node = self
for c in w:
idx = 26 if c == ' ' else ord(c) - ord('a')
if node.children[idx] is None:
node.children[idx] = Trie()
node = node.children[idx]
node.v += t
node.w = w
def search(self, pref):
node = self
for c in pref:
idx = 26 if c == ' ' else ord(c) - ord('a')
if node.children[idx] is None:
return None
node = node.children[idx]
return node
class AutocompleteSystem:
def __init__(self, sentences: List[str], times: List[int]):
self.trie = Trie()
for a, b in zip(sentences, times):
self.trie.insert(a, b)
self.t = []
def input(self, c: str) -> List[str]:
def dfs(node):
if node is None:
return
if node.v:
res.append((node.v, node.w))
for nxt in node.children:
dfs(nxt)
if c == '#':
s = ''.join(self.t)
self.trie.insert(s, 1)
self.t = []
return []
res = []
self.t.append(c)
node = self.trie.search(''.join(self.t))
if node is None:
return res
dfs(node)
res.sort(key=lambda x: (-x[0], x[1]))
return [v[1] for v in res[:3]]
# Your AutocompleteSystem object will be instantiated and called as such:
# obj = AutocompleteSystem(sentences, times)
# param_1 = obj.input(c)
class Trie {
Trie[] children = new Trie[27];
int v;
String w = "";
void insert(String w, int t) {
Trie node = this;
for (char c : w.toCharArray()) {
int idx = c == ' ' ? 26 : c - 'a';
if (node.children[idx] == null) {
node.children[idx] = new Trie();
}
node = node.children[idx];
}
node.v += t;
node.w = w;
}
Trie search(String pref) {
Trie node = this;
for (char c : pref.toCharArray()) {
int idx = c == ' ' ? 26 : c - 'a';
if (node.children[idx] == null) {
return null;
}
node = node.children[idx];
}
return node;
}
}
class AutocompleteSystem {
private Trie trie = new Trie();
private StringBuilder t = new StringBuilder();
public AutocompleteSystem(String[] sentences, int[] times) {
int i = 0;
for (String s : sentences) {
trie.insert(s, times[i++]);
}
}
public List<String> input(char c) {
List<String> res = new ArrayList<>();
if (c == '#') {
trie.insert(t.toString(), 1);
t = new StringBuilder();
return res;
}
t.append(c);
Trie node = trie.search(t.toString());
if (node == null) {
return res;
}
PriorityQueue<Trie> q
= new PriorityQueue<>((a, b) -> a.v == b.v ? b.w.compareTo(a.w) : a.v - b.v);
dfs(node, q);
while (!q.isEmpty()) {
res.add(0, q.poll().w);
}
return res;
}
private void dfs(Trie node, PriorityQueue q) {
if (node == null) {
return;
}
if (node.v > 0) {
q.offer(node);
if (q.size() > 3) {
q.poll();
}
}
for (Trie nxt : node.children) {
dfs(nxt, q);
}
}
}
/**
* Your AutocompleteSystem object will be instantiated and called as such:
* AutocompleteSystem obj = new AutocompleteSystem(sentences, times);
* List<String> param_1 = obj.input(c);
*/