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MATCH (k:K)
WHERE k.Id IN ['1']
WITH k as a
OPTIONAL MATCH path = (a)-[*1..3]-(e:E)
return path
UNION ALL
MATCH (k:K)
WHERE k.Id IN ['1']
WITH k as a
OPTIONAL MATCH path =(a)-[*1..3]-(m:M)
return path
UNION ALL
MATCH (k:K)
WHERE k.Id IN ['1']
WITH k as a
OPTIONAL MATCH path =(a)-[*1..3]-(l:L)
RETURN path
Since this issue was labeled as "more info needed" but no response has been received for 15 days. Now the issue is closed. Please feel free to create a new one with more info if you have more questions.
Environment:
在阿里云计算巢购买的 tugraph
Describe the bug
执行下面的cypher会报错,在neo4j是正常执行的
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