Fails to detect repeated operators in a single expression (e.g. a &&& b)

[ItsAshleyJ182]

Parsing search strings such as 'a &&& b' or even 'a & & b' generates a result of
AND( Symbol('a'), Symbol('yes') )
When realistically, neither expression makes that much sense syntactically. Looking at the code, there only seems to be checking for repeated Symbol objects. Is this a design decision that was made during development? I see this leading to potential instances where a user would send in an incorrect search string that evaluates to an unintended result.

[pombredanne]

@banjoanderson this is eventually a bug. Fixes welcomed if you feel like it.

[pombredanne]

One approach to resolve this would be to iterate on the tokenize() results

boolean.py/boolean/boolean.py

Line 359 in 6ff1316

def tokenize(self, expr):

at the start of parse()

boolean.py/boolean/boolean.py

Line 179 in 6ff1316

def parse(self, expr, simplify=False):

eventually in another function and raise ParseError for illegal token sub-sequences such as repeated & and likely a few other cases

[pombredanne]

And btw, sorry for the late reply to your ticket! and thank you for using boolean.py!