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I have a column of a custom type, and I want a reference to the parent for the child. I want to be able to do:
foo = Participant.from_username('foo') foo.email.send(message)
... and inside send have access to foo.username, etc.
send
foo.username
The text was updated successfully, but these errors were encountered:
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I have a column of a custom type, and I want a reference to the parent for the child. I want to be able to do:
... and inside
send
have access tofoo.username
, etc.The text was updated successfully, but these errors were encountered: