Find the Valence Shell using this Python program
It's a solver to your chemistry homeworks / exams, also helped me (SynnK) (dev) on my own exam.
n= 8 | l= 3 | m= 2 | s = -1/2
8F¹³
[ ⇅ | ⇅ | ⇅ | ⇅ | ⇅ | ⇅ | ↑ ]
---
n= 8 | l= 3 | m= -2 | s = +1/2
8F²
[ ↑ | ↑ | | | | | ]
n = the number (e.g: 3)
l = the layer (e.g: 2 | 3D)
m = the position (from -l to +l)
|-->( e.g: -2 = [-2 | -1 | 0 | +1 | +2] )
|--> Given -1: going to run all the way to -1, using S (spin)
s = spin/how to find the atom (+1/2 or -1/2 | e.g = +1/2 = 1)
if m = -1 and s = +1/2:
This is our table:
[-2 | -1 | 0 | +1 | +2]
^-- is where we want to go but using the + (plus) way
^-- plus way is the default starting found method
[^ | ^ | | | ]
^-----^----- both are up arrows because we are using the + (plus) way (up arrow)
^-----------> now its just count how much arrows there are!
Our Valence Layer / Valence Electron / Valence Shell is 3D²
3D2 is our last layer! cool, right?!