A better example of issues one can run into with variadic iteratees #54
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As indicated in the example I tried
['1', '2', '3'].forEach(parseInt);
and gotundefined
as expected. I am not sure why would it output anything else, since forEach doesn't return anything, but when I run['1', '2', '3'].map(parseInt);
I got[1, NaN, NaN]
which is not what I expected. So I think this better illustrates the problem.